2x^2-3x+5=4.8

Solution for 2x^2-3x+5=4.8 equation:

2x^2-3x+5=4.8

We move all terms to the left:

2x^2-3x+5-(4.8)=0

We add all the numbers together, and all the variables

2x^2-3x+0.2=0

a = 2; b = -3; c = +0.2;
Δ = b2-4ac
Δ = -32-4·2·0.2
Δ = 7.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{7.4}}{2*2}=\frac{3-\sqrt{7.4}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{7.4}}{2*2}=\frac{3+\sqrt{7.4}}{4}
$